## 1 TOP SPEED OF 2020 LOTUS EVORA GT According to Lotus, the top speed of the 2020 Lotus Evora GT is 188 mph. Let's see. Using my method and my own formulas except for the rolling resistance, the MSA or Motorsports Standard Atmosphere of 60 F, 29.92 inHg and 0% humidity -> 1.223 kg/m^3 air density, the auto manufacturer's recommended and standard tire pressure of 32 psi:

Hc = (0.0000055652pAfCdS^3+ 0.0026667CrSWt)/Pf -> my formula

Pf = 5,252Hc/EpTp -> my formula

Cr = 0.005 + (14.5 / P) (0.01 + 0.0095 (1.609S / 100)^2) -> https://www.engineeringtoolbox.com/rolling-friction-resistance-d_1303.html

2020 Lotus Evora GT (Manual)

Where:

Hc = 410 (416 PS) horsepower (crank)
Ep = 7,000 rpm (peak engine power)
Tp = 310 lb-ft @3,500 rpm -> 420 Nm (peak torque)
p = 1.223 kg/m^3 (Rho or air density)
Af = 20.56 sq ft -> 1.92 sq mt (frontal area)
Cd = 0.35 (drag coefficient)
Wt = 3,112 + 165 lbs (driver) -> 3,277 lbs, 1,487 kgs (curb weight plus driver)
Pf = 0.99231 (powertrain factor)
Cr = 0.0490 @32.0 psi (coefficient of rolling resistance)
P = 32.0 psi (tire pressure)
S = 188.15 mph @32.0 psi (top speed)

Hc = 410 = (0.0000055652x1.223x20.56x0.35x188.15^3 + 0.0026667x0.0490x188.15x3,277)/0.99231
= (326.22 + 80.57)/0.99231
= 409.94
= 410

Pf = 0.99231 = 5,252x410/7,000x310
= 2,153,320/2,170,000
= 0.99231

Cr = 0.0490 = 0.005 + (14.5/32.0)(0.01 + 0.0095(1.609X188.15/100)^2)
= 0.005 + (0.453125)(0.01 + 0.0095(3.0273)^2
= 0.005 + (0.453125)(0.01 + 0.087063)
= 0.005 + (0.4531)(0.097063)
= 0.005 + 0.0440
= 0.0490

1y ago by NatsM  hostboy  1y ago

Great info! I love OmniCalculator!

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